Answer:
Time to complete one revolution = 1.31 x 10^(-8) s
Step-by-step explanation:
In motion of charges in electromagnetic fields, we know that ;
R = mv/qB
Where,
R is radius of the circular path
q is the charge on the particle
m is the mass of the particle moving v is constant speed
B is magnetic field
Now in the question, we are given value of q/m. Let's rearrange the equation to show that;
r = mv/qB
(q/m)•(rB) = v - - - - (1)
Now, in circular motion, we know that; Period; T = 2πr/v
Thus, let's make v the subject.
v = 2πr/T - - - - - (2)
Now equating eq 1 to eq 2,we obtain;
(q/m)•(rB) = 2πr/T
r will cancel out to give ;
(q/m)B = 2π/T
Making T the subject, we get;
T = 2π/[(q/m)B]
From the question,
B = 0.84 T
q/m = 5.7 × 10^(8) C/kg
Thus,
T = 2π/[5.7 × 10^(8) x 0.84] = 1.31 x 10^(-8) s