Question

A 61.0 cm wire carries a current of 1.00 A. The wire is formed into a single circular loop and placed in a magnetic field of intensity 1.00 T. Find the maximum torque that can act on the loop.

Answer 1

0.029 Nm

Step-by-step explanation:

We are given that

Length of wire,l=61 cm=
`(61)/(100)=0.61 m`

1 m=100 cm

Current,I=1 A

Magnetic field intensity,B=1 T

We have to find the maximum torque that can act on the loop.

`r=(l)/(2\pi)=(61)/(2* 3.14)=0.097 m`

Where
`\pi=3.14`

Torque,
`\tau=IAB=\pi r^2IB`

Substitute the values

`\tau=3.14* (0.097)^2* 1* 1=0.029 Nm`