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A circular coil of 234 turns has a radius of 1.96 cm. (a) Calculate the current that results in a magnetic dipole moment of magnitude 2.57 A·m2. (b) Find the maximum magnitude of the torque that the coil, carrying this current, can experience in a uniform 42.7 mT magnetic field.

User Benzy
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1 Answer

6 votes

Answer:

a)
I = 9.1785 A

b) τ = 0.109 N m (max)

Step-by-step explanation:

given

magnetic dipole moment μ = 2.57 Am²

number of turns N = 234

radius r = 1.96 cm = 0.0196 m

using μ = N I A

where I is current and A is area

I = μ/NA


I= (2.57)/(234 *\pi r^2)


I= (2.57)/(234 *\ 3.14 *(0.0196) ^2)


I = (2.57)/(0.28)


I = 9.1785 A

for max torque

we know τ = μΒ

τ = 2.57 ×0.0427

τ = 0.109 N m (max)

User Azania
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4.6k points