Answer:
The molecular formula of the compound :
![C_4H_6O_2](https://img.qammunity.org/2021/formulas/chemistry/college/edzoe9bkwces0xveb48oescmea2xnltui1.png)
Step-by-step explanation:
The empirical formula of the compound =
![C_2H_3O](https://img.qammunity.org/2021/formulas/chemistry/college/y2makw4c03sf0et7ras1vx9iprhf356q9e.png)
The molecular formula of the compound =
![C_(2n)H_(3n)O_n](https://img.qammunity.org/2021/formulas/chemistry/college/929o9nc9jqyzngi4v17qn7virct8iitzvr.png)
The equation used to calculate the valency is :
![n=\frac{\text{molecular mass}}{\text{empirical mass}}](https://img.qammunity.org/2021/formulas/chemistry/high-school/cf58l8qcji3pjww671gruk18lel697nzjf.png)
We are given:
Mass of molecular formula = 86 g/mol
Mass of empirical formula = 43 g/mol
Putting values in above equation, we get:
![n=(86g/mol)/(43g/mol)=2](https://img.qammunity.org/2021/formulas/chemistry/college/2wvwq8fnz7wu4tbdi8vrw4ojjlgovjhvh0.png)
The molecular formula of the compound :
![C_(2* 2)H_(3* 2)O_2=C_4H_6O_2](https://img.qammunity.org/2021/formulas/chemistry/college/4wm4gsgbpjrzquw0417qes1eu0bkghaq3v.png)