Question

Solve for x and round to the nearest tenth for both (please:) )

Answer 1

see explanation

Explanation:

using the sine ratio in the right triangle.

sin23° =
`(opposite)/(hypotenuse)` =
`(x)/(7)` ( multiply both sides by 7 )

7 × sin23° = x , then

x ≈ 2.7 ( to the nearest tenth )

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using the tangent ratio in the right triangle

tan x =
`(opposite)/(adjacent)` =
`(27)/(17)` , then

x =
`tan^(-1)` (
`(27)/(17)` ) ≈ 57.8° ( to the nearest tenth )