Question

cheAt an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and falls through a vertical height of 2.77 m, what is her speed at the bottom of the slide

Answer 1

`v \approx 7.371\,(m)/(s)`

Step-by-step explanation:

The swimmer can be modelled by the Principle of Energy Conservation. The speed is derived herein:

`m_(swimmer)\cdot g \cdot h = (1)/(2)\cdot m_(swimmer)\cdot v^(2)`

`v = √(2\cdot g \cdot h)`

`v = \sqrt{2\cdot (9.807\,(m)/(s^(2)) )\cdot (2.77\,m)}`

`v \approx 7.371\,(m)/(s)`