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Consider the following function and express the relationship between a small change in x and the corresponding change in y in the form dy equals f prime (x )dx. f (x )equals StartFraction 1 Over x Superscript 12 EndFraction

User Sureshhh
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1 Answer

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Answer:

Required relation is
dy=(-12dx)/(x^(13)).

Explanation:

Given,


f(x)=(1)/(x^(12)) be such that,
dy=f'(x)dx.

To show relationship between a small change in x and corresponding change in y, consider,


dy=f'(x)dx


=(d)/(dx)(f(x))dx


=(d)/(dx)(x^(-12))dx


=-12x^(-12-1)dx


\therefore dy=(-12dx)/(x^(13))

which is the required relation.

User SimUser
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