128k views
5 votes
Under ideal​ conditions, a service bay at a Fast Lube can serve 7 cars per hour. The effective capacity of a Fast Lube service bay is 5.7 cars per​ hour, with efficiency known to be 0.90.

The minimum number of service bays Fast Lube needs to achieve an anticipated production of 150 cars per 8​-hour day​ = _______ service bays ​(enter your response rounded up to the next whole​ number).

User Jmunsch
by
8.1k points

1 Answer

3 votes

Answer:

4 service bays

Step-by-step explanation:

Efficiency is the performance of any task with best outcome in a minimum input. Effective efficiency is the actually efficiency that is effectively making a output in minimum available resources.

Actual output = Effective Capacity x Efficiency = 5.7 x 0.9 = 5.13 cars / hour

In a 8 hour day, one bay accommodates =Actual output per hour x Numbers of hours in a day = 5.13 x 8 = 41.04 cars

To deal with 150 cars per an 8 hour day =Anticipated production / production per bay per day = 150 cars / 41.04 cars per day = 3.65 service bays,

As they can't build 0.65 service bay, and 3 service bays cannot accommodate all 150 cars, Fast Lube would need 4 service bays to achieve the target volume of 150 cars.

User Asmodianis
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.