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Under ideal​ conditions, a service bay at a Fast Lube can serve 7 cars per hour. The effective capacity of a Fast Lube service bay is 5.7 cars per​ hour, with efficiency known to be 0.90.

The minimum number of service bays Fast Lube needs to achieve an anticipated production of 150 cars per 8​-hour day​ = _______ service bays ​(enter your response rounded up to the next whole​ number).

User Jmunsch
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Answer:

4 service bays

Step-by-step explanation:

Efficiency is the performance of any task with best outcome in a minimum input. Effective efficiency is the actually efficiency that is effectively making a output in minimum available resources.

Actual output = Effective Capacity x Efficiency = 5.7 x 0.9 = 5.13 cars / hour

In a 8 hour day, one bay accommodates =Actual output per hour x Numbers of hours in a day = 5.13 x 8 = 41.04 cars

To deal with 150 cars per an 8 hour day =Anticipated production / production per bay per day = 150 cars / 41.04 cars per day = 3.65 service bays,

As they can't build 0.65 service bay, and 3 service bays cannot accommodate all 150 cars, Fast Lube would need 4 service bays to achieve the target volume of 150 cars.

User Asmodianis
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