Answer: option B
Explanation: each cell is suppose to have an emf and an internal resistance.
Let E1 be the emf of the first battery and E2 be the emf of the second battery.
Et is the total emf.
Going by the connection described above, it is a series arrangement.
Hence the total emf is calculated as sum of individual emf
Et = E1 + E2
But each cell are identical, hence E1 = E2 = E
Et = E + E = 2E.
Hence the total voltage is twice the voltage.
Since the connection is a series arrangement, the current passing through each cell is the same.
These points have made option B the correct answer.