Question

H=3+14t-5t^2
What is its maximum height

Answer 1

12.8

Explanation:

Given a parabola in standard form , ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

h = 3 + 14t - 5t² ← is in standard form

with a = - 5 and b = 14, thus

`x_(vertex)` = -
`(14)/(-10)` = 1.4

Substitute t = 1.4 into h for maximum height

h = 3 + 14(1.4) - 5(1.4)²

= 3 + 19.6 - 9.8 = 12.8