Question

A light ray in air hits piece of quartz at a 39.0 deg angle. Inside the quartz, the light slows down to 2.06*10^8 m/s. At what angle does the light travel in the quarts? (Hint: find n.)

(Unit=deg)

Answer 1

Angle of light at which it will travel in the quartz is given as

`\theta = 25.6^o`

Step-by-step explanation:

As we know that the refractive index of a medium is the ratio of speed of light in air and speed of light in the medium

So we will have

`\mu = (c)/(v)`

here we have

`\mu = (3 * 10^8)/(2.06 * 10^8)`

`\mu = 1.456`

now by Snell's law we have

`n_1 sin\theta_1 = n_2 sin\theta_2`

`1 sin39 = 1.456 sin\theta`

`\theta = 25.6^o`