5x^2=60-20x is rewritten as 5(x-p)^2+q=0 what is the value of Q

Question

asked Jul 7, 2021 191k views

2 Answers

Jeff Treuting · Answer 1 · 2021-07-09T06:57:35+0000

Answer:

-80

Explanation:

5x² + 20x - 60 = 0

5(x² + 4x) - 60 = 0

5[x² + 2(x)(2) + 2² - 2²] - 60 = 0

5(x - 2)² - 5(4) - 60 = 0

5(x - 2)² - 20 - 60 = 0

5(x - 2)² - 80 = 0