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5x^2=60-20x is rewritten as 5(x-p)^2+q=0 what is the value of Q
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5 votes
5x^2=60-20x is rewritten as 5(x-p)^2+q=0 what is the value of Q

User Joni Jones
by
3.9k points

2 Answers

6 votes

Answer:

-80

Explanation:

5x² + 20x - 60 = 0

5(x² + 4x) - 60 = 0

5[x² + 2(x)(2) + 2² - 2²] - 60 = 0

5(x - 2)² - 5(4) - 60 = 0

5(x - 2)² - 20 - 60 = 0

5(x - 2)² - 80 = 0

User Jeff Treuting
by
3.3k points
4 votes

Answer:

q=-5(x-p)^2

Explanation:

User Apsdehal
by
4.0k points
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