Question

Charge of 0.0 5C moves a negative charge upward due to a 2 N Force exerted by an electrical field. What is the magnitude and direction of the electric field?

•0.03 n/c upward
•0.03 n/c downward
•40 n/c upward
•40 n/c downward

Answer 1

Step-by-step explanation:

E2020

Answer 2

•40 n/c downward

Step-by-step explanation:

Electric Field and Electric Force

Suppose a particle has a net charge q. A surrounding electric field is produced such that any positive charge placed feels a force makes the charges get farther. If the second charge is negative, then the force makes them get closer. The magnitude of the electric field can be measured if we know the force F exerted to the second charge as

`\displaystyle E=(F)/(q)`

The charge described in the question is positive and moves a negative charge upward with a force of 2 N. This means the first charge is above the second charge and its electric field points downward.

Compute the magnitude

`\displaystyle E=(2)/(0.05)=40\ N/c`

Answer: •40 n/c downward