Question

The force of repulsion between two identical positive charges is 0.800 N when the charges are 0.100 m apart. Find the value of each charge.

Answer 1

Value of each charge is given as

`q = 9.43 * 10^(-7) C`

Step-by-step explanation:

As we know that electrostatic force between two charges is given as

`F = (kq_1 q_2)/(r^2)`

here we know that

`q_1 = q_2 = q`

`F = 0.800 N`

r = 0.100 m

now we have

`F = ((9* 10^9) q^2)/((0.100)^2)`

`0.800 = 9* 10^(11) q^2`

`q = 9.43 * 10^(-7) C`