Answer:
666.7 Hz
Step-by-step explanation:
Light is an example of electromagnetic wave. Electromagnetic waves consist of oscillations of electric and magnetic fields that propagate through space. They are transverse waves, and they all travel through a vacuum at a speed of
![c=3.0\cdot 10^8 m/s](https://img.qammunity.org/2021/formulas/chemistry/middle-school/dz068hai8fc255uekvuotgsus36jj1167k.png)
called speed of light.
The relationship between frequency and wavelenght for an electromagnetic wave is given by the equation:
![c=f\lambda](https://img.qammunity.org/2021/formulas/physics/high-school/2yb9modtin2v49rpvhtimpqykq47m2vyy3.png)
where
f is the frequency of the wave
is its wavelength
In this problem, the light wave has a wavelength of
![\lambda=4.5\cdot 10^5 m](https://img.qammunity.org/2021/formulas/physics/middle-school/xf299gk4ck2ozwfrdkm5vaixprkkgf0ny2.png)
Therefore, by using the equation above, we can find its frequency:
![f=(c)/(\lambda)=(3.0\cdot 10^8)/(4.5\cdot 10^5)=666.7 Hz](https://img.qammunity.org/2021/formulas/physics/middle-school/hbd5vy5fbxntjmbaifozjb0hslihmw98kz.png)