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Solve 3(a+1)^2 +2=11 with 2 different methods

User Bolanle
by
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1 Answer

5 votes

Answer:


a = - 1 - √(3) \: or \: a = - 1 + √(3)

Explanation:

We want to solve


3 {(a + 1)}^(2) + 2 = 11

with two different methods.

Subtract 2 from both sides:


3 {(a + 1)}^(2) = 11 - 2 \\ 3 {(a + 1)}^(2) = 9

Divide through by 3


{(a + 1)}^(2) = 3

Take square root:


a + 1 = \pm √(3)


a = - 1\pm √(3)


a = - 1 - √(3) \: or \: a = - 1 + √(3)

Method 2:

The given equation is


3 {(a + 1)}^(2) + 2 = 11

Expand


3( {a}^(2) + 2a + 1) + 2 = 11

Subtract 11


3( {a}^(2) + 2a + 1) - 9 = 0

Divide through by 3


{a}^(2) + 2a + 1 - 3 = 0 \\ {a}^(2) + 2a - 2 = 0

Use the quadratic formula:


a = \frac{ - 2 \pm \sqrt{ {2}^(2) - 4 * 1 * - 2} }{2 * 1}


a = ( - 2 \pm √( 12) )/(2)


a = ( - 2 \pm2 √(3) )/(2)


a = - 1 \pm√(3)


a = - 1 - √(3) \: or \: a = - 1 + √(3)

User Ccgillett
by
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