Question

What are the x-intercepts of y=sin(x)+1

Answer 1

`x = n\pi + ( { - 1)}^(n) * (3\pi)/(2)`

Explanation:

We want to find the x-intercepts of

`y = \sin(x) + 1`

At x-intercept, y=0.

`0 = \sin(x) + 1`

`\sin(x) = - 1`

Take sine inverse of both sides to get:

`x = { \sin }^( - 1) ( - 1)`

`x = n\pi + ( { - 1)}^(n) { \sin }^( - 1) ( 1)`

The x-intercepts are:

`x = n\pi + ( { - 1)}^(n) * (3\pi)/(2)`

for n being an integer