What are the x-intercepts of y=sin(x)+1

Question

asked Feb 27, 2021 111k views

1 Answer

Alayne · Answer 1 · 2021-03-04T11:24:27+0000

Answer:

$x = n\pi + ( { - 1)}^(n) * (3\pi)/(2)$

Explanation:

We want to find the x-intercepts of

$y = \sin(x) + 1$

At x-intercept, y=0.

$0 = \sin(x) + 1$

$\sin(x) = - 1$

Take sine inverse of both sides to get:

$x = { \sin }^( - 1) ( - 1)$

$x = n\pi + ( { - 1)}^(n) { \sin }^( - 1) ( 1)$

The x-intercepts are:

$x = n\pi + ( { - 1)}^(n) * (3\pi)/(2)$

for n being an integer