Question

3/2y-3+5/3 when y=6 and z=3

Answer 1

`5 (1)/(3)`

Explanation:

Assuming We want to evaluate

`(3)/(2y - 3) + (5)/(3) z`

When y=6 and z=3.

We substitute to get:

`(3)/(2 * 6 - 3) + (5)/(3) * 3`

We multiply to get:

`(3)/(12 - 3) + (15)/(3)`

We simplify the denominator to get:

`(3)/(9) + (15)/(3)`

Reduce the first fraction:

`(1)/(3) + (15)/(3)`

Add the numerator and keep one denominator for they are like fractions

`(16)/(3)`

Write as a mixed number:

`5 (1)/(3)`