Question

(-3,2) and ( 2,13) slope interept equation

Answer 1

Given:

The points are (-3, 2) and (2, -13).

To find:

Slope-intercept form of the equation.

Solution:

Here
`x_1=-3, y_1=2, x_2=2, y_2=-13`.

Slope of the line:

`$m=(y_2-y_1)/(x_2-x_1)`

`$m=(-13-2)/(2-(-3))`

`$m=(-15)/(5)`

m = -3

Using point-slope formula:

`y-y_1=m(x-x_1)`

`y-2=-3(x-(-3))`

`y-2=-3(x+3)`

`y-2=-3x-9`

Add 2 on both sides.

`y-2+2=-3x-9+2`

`y=-3x-7`

Slope-intercept form of the equation is y = -3x - 7.