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How many atoms of copper will react with 33.9 L of nitrogen at STP to produce copper(l)nitride?

User CJ Teuben
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1 Answer

6 votes

Answer:

9.09 x 10²³ atoms

Step-by-step explanation:

Given parameters:

Volume of nitrogen = 33.9L

Condition of reaction = STP

Unknown:

Number of atoms of Copper reacting = ?

Solution:

Let us write the reaction equation first;

3Cu + N₂ → Cu₃N₂

We have to work from the know to unknown specie.

With the information given, let us find the number of moles of nitrogen since it is the known specie;

At STP;

Number of moles =
(volume of gas)/(22.4) =
(33.9)/(22.4) = 1.51 moles

From the balanced equation;

1 mole of Nitrogen gas will give 1 mole of copper(II)nitride

1.51 moles of Nitrogen gas will produce 1.51 moles of copper(II)nitride

To find the number of atoms;

1 mole of a substance contains 6.02 x 10²³ atoms

1.51 moles of a substance will contain 1.51 x 6.02 x 10²³ atoms

= 9.09 x 10²³ atoms

User Jproffitt
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