The single logarithm term would be log(b - x)
Step-by-step explanation:
Given:
(logₓ a) (logₐ b)
We have to write it in single logarithm
We have to use the formula
![log_a (m) = (log (m))/(log(a)) \\\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yg93b5mfzd865f7emw8g4ctof4krmb39x3.png)
So, we can write (logₐ b) as
and (logₓ a) as
![(log(a))/(log(x))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n7yvhjzac4bhn8gl6w32lbmxtkyfgs60dy.png)
So,
(logₓ a) (logₐ b) =
![(log (a))/(log(x)) X (log (b))/(log (a))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k8j3iime02wrqp5t0bd3fgyuz10umtpj71.png)
=
![(log(b))/(log(x))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fqvib80l0yb0broapuvnr2e5hhg6jyb40p.png)
= log (b - x)
Therefore, the single logarithm term would be log(b - x)