Final answer:
The chemistry query deals with an experiment to calculate the half-life in a second-order chemical reaction, which in the given scenario is determined to be 18 minutes using a rate constant of 0.0576 L mol⁻¹ min⁻¹ and an initial concentration of 0.200 mol L⁻¹.
Step-by-step explanation:
The question pertains to a chemistry experiment focusing on the concept of reaction rates and half-lives. When setting up an experiment with a reactant concentration of 2.0 mol/L, and varying catalyst concentrations, one must measure the half-life of the reaction. This can be accomplished by observing the time needed for the concentration of the reactant to decrease to half its initial value. In a second-order reaction, the half-life can be calculated by applying a specific mathematical formula for second-order reactions, which takes into account the rate constant and initial concentrations. Given the rate constant of 0.0576 L mol⁻¹ min⁻¹ and an initial reactant concentration of 0.200 mol L⁻¹, the half-life is calculated to be 18 minutes. To determine the completion percentage of the reaction, one can use the remaining concentration after a number of half-lives, subtracting this from the initial concentration and then dividing by the initial concentration, multiplying by 100.