The pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.
Step-by-step explanation:
Pressure acting on any surface is the amount of force experienced by that surface in a given area. So it is the ratio of force to area of the object under consideration.
As here the force is said to be 50 N and the area is said to be 20 m², the pressure will be
![Pressure = (Force)/(Area) = (50)/(20)=2.5 Nm^(2)](https://img.qammunity.org/2021/formulas/physics/middle-school/n1v4xcu19r1360nyyhetlxj7paltbjjlxk.png)
So, pressure is inversely proportional to the area and directly proportional to the force acting on the surface. As it can be seen that on decreasing the area to 0.5 m², there will be increase in the pressure as shown below,
![Pressure = (50)/(0.5) = 100 Nm^(2)](https://img.qammunity.org/2021/formulas/physics/middle-school/w3je2b6jq182x81qyz8kyu5gs6h2f1slv7.png)
Thus, the pressure increased to 100 Nm² from 2.5 Nm² on decreasing the area from 20 m² to 0.5 m².
Similarly, if 10 Pa pressure is acting on an area of 3 m², then the force acting on this region will be the product of pressure with the area.
![Force = Pressure * Area = 10 * 3 = 30 N.](https://img.qammunity.org/2021/formulas/physics/middle-school/uscsm4pepwkdxucdktl5nhk9ctdgk86khr.png)
Thus, the pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.