Answer:
5
Explanation:
The maximum or minimum of a quadratic function occurs at x= −b/2a. If a is negative, the maximum value of the function is f(−b/2a). If a is positive, the minimum value of the function is f(−b/2a)
fmax
c=ac²+bc+c occurs at c=−b/2a
Find the value of c
equal to −b/2a
c=−b/2a
Substitute in the values of a
and b
c=−120/2(−12)
Remove parentheses.
c=−120/2(−12)
c=−60/−12
c= 5