Answer:

Explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://img.qammunity.org/2021/formulas/mathematics/high-school/srd3lcabzf3q3mdcxpt2b7tfuwf6rv1rsq.png)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have

and by replacing in the integral we have
![V=\pi \int \limit_(x1)^(x2)[(lnx+5)^2-((1)/(2)x+3)^2]dx\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/mms930wpyt9de3axxuf2qz5jgc1qhyhw9s.png)
and by evaluating in the limits we have

Hope this helps
regards