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3 votes
Find the values of the integers x and y: 10x^(2)-90x+2xy+y^(2)+225=0

User Hruske
by
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1 Answer

5 votes

Answer:

(x, y) = (5, -5)

Explanation:

The equation can be rewritten as ...

9x^2 -90x +225 +x^2 +2xy +y^2 = 0

9(x^2 -10x +25) +(x +y)^2 = 0

9(x -5)^2 +(x +y)^2 = 0

The only way the sum of squares can be zero is for each square to be zero:

x -5 = 0

x +y = 0

Then x = 5 and y = -5.

User Marsellus Wallace
by
5.8k points
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