Find the valuesof integers x and y: x^(8)+16y^(8)=0

asked Feb 23, 2021 133k views

5 votes

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4 votes

Answer:

x=0,

y=0

Explanation:

$x^8+16y^8=0\\(x^(2)) ^(4) +16(y^(2)) ^(4) =0\\x^2\geq 0,y^2\geq 0\\sum~ of ~two ~positive~ integers ~is~ zero~ if~ each=0\\so~x=0,~y=0$

Snickbrack answered Mar 1, 2021

4.6k points

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