Question

A student has a solution of 3.11 M MgSO4. What volume (in mL) of

the original solution is needed to make 232.0 mL of 2.44 M MgSO4?

Answer 1

182mL

Step-by-step explanation:

Given parameters:

Molarity of solution = 3.11M

New volume = 232mL = 0.232dm³

New molarity = 2.44M

Unknown:

Volume of original solution = ?

Solution:

We know the full information about the new solution we want to obtain. From this, we should find the number of moles.

Using the number of moles, we can find the original volume.

Molarity =
`(number of moles )/(volume)`

New number of moles = molarity x volume = 2.44 x 0.232

= 0.57moles

The original volume will be;

Volume =
`(number of moles )/(molarity)` =
`(0.57)/(3.11)` = 0.182dm³ or 182mL