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Find 2 cube number that is greater then 20 but less than 50

User Seph
by
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1 Answer

2 votes


20\leqslant x {}^(3) \leqslant 50


\sqrt[3]{20} \leqslant x \leqslant \sqrt[3]{50}


2.714 \leqslant x \leqslant 3.684


x = 3


x = 3.5

verify your answer:


3 {}^( 3) = 27


20\leqslant27 \leqslant 50


3.5 {}^(3) = 42.875


20 \leqslant 42.875 \leqslant 50

User Maxenglander
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