Question

Solve the system of linear equations.

6x - 2y = -18

2x - 2y = -2

Answer 1

x = -4, y = -3.

Explanation:

Solving: 6x-2y = -18 2x-2y = -2 Using Substitution Method. Expressing x as a function of y (from the first equation) x = (-18 +2y)/6 Substituting this expression into the second equation: 2(-18-2y)/6-2y = -2 then Simplifying this expression: (-8)y = 24 or y = -3 Now you can, substitute y = -3 back into the x expressed as a function of y: x = (-18+2y)/6 = -4

Answer 2

x = -4

y = -3

Explanation:

to solve the system of linear equation we say that let

6x - 2y = -18........................ equation 1

2x - 2y = -2.......................... equation 2

from equation 2

2x - 2y = -2.......................... equation 2

2x = -2 + 2y

divide both sides by 2

2x/2 = ( -2 + 2y)/2

x = ( -2 + 2y)/2................................ equation 3

substitute for x in equation 1

6x - 2y = -18........................ equation 1

6[( -2 + 2y)/2] - 2y = -18

-6 + 6y- 2y = -18

collect the like terms

6y - 2y = -18 + 6

4y = -12

divide both sides by the coefficient of y which is 4

4y/4 = -12/4

y = -3

put y = -3 in equation 3

x = ( -2 + 2y)/2................................ equation 3

x = -2 + 2(-3)/2

x = -2-6/2

x = -8/2

x = -4

therefore the value of x and y in the equation is -4 and -3 respectively.