Answer:
Part 1) When the amount of calling is 450 minutes the two plans cost the same
Part 2) When the two plans cost the same , the cost is $68.50
Explanation:
Part 1) For what amount of calling do the two plans cost the same?
Let
x ---> the number of minutes
y ----> the total cost
we know that
The linear equation in slope intercept form is equal to
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
where
m is the slope or unit rate of the linear equation
b is the y-intercept or initial value
In this problem we have
Plan A
The slope is equal to
![m=\$0.11\ per\ minute](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4222stux5lysuwhw0okpfg5jkx6v5sgzjs.png)
The y-intercept is
![b=\$19](https://img.qammunity.org/2021/formulas/mathematics/middle-school/w4ui0whrrcci58yzlgr0gmmmoqu4zjghiw.png)
substitute
----> equation A
Plan B
The slope is equal to
![m=\$0.13\ per\ minute](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lf0p2oel6vrtcxo5uhjq847pdc83b8m8gc.png)
The y-intercept is
![b=\$10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9e06ys9b2d1py1d66x4xmnfx03mpk3e7v7.png)
substitute
----> equation B
Equate equation A and equation B
![0.13x+10=0.11x+19](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wb8e1snh4k2q0kfbnxjvh93t6ndip2mwwr.png)
solve for x
![0.13x-0.11x=19-10\\0.02x=9\\x=450](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9xn24hwul2j1dkppbqamlkye41xgsjpxvn.png)
therefore
When the amount of calling is 450 minutes the two plans cost the same
Part 2) What is the cost when the two plans cost the same?
substitute the value of x=450 minutes in equation A or equation B and solve for y
![y=0.11(450)+19=68.5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/j0rnmbs738am3p5t44r0u0xn9u1vvirigv.png)
therefore
When the two plans cost the same , the cost is $68.50