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A 159.0L sample of O2 gas is collected at 2.20 atm and 45C. If the temperature remains constant, what volume will the gas occupy if the pressure is decreased to 1.90 atm?

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Answer:

184.1 L

Explanation:the following data were obtained from the question:

V1 (initial volume) = 159.0L

P1 (initial pressure) = 2.20 atm

P2 (final pressure) = 1.90 atm

V2 (final volume) =.?

Since the temperature is constant, the gas is obeying Boyle's law. Using the Boyle's law equation P1V1 = P2V2, we can easily calculate the final volume of the gas as illustrated below:

P1V1 = P2V2

2.2 x 159 = 1.9 x V2

Divide both side by 1.9

V2 = (2.2 x 159) /1.9

V2 = 184.1 L

Therefore, the final volume of the gas is 184.1 L

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