Question

Write an equation in slope-intercept form of the line with the given parametric equations.

x = -3t+5
y = 8t+9

Answer 1

y = (-8/3)x + 67/3

Explanation:

x = -3t + 5

t = (5 - x)/3

y = 8t + 9

y = 8(5 - x)/3 + 9

y = 40/3 - 8x/3 + 9

y = -8x/3 + 67/3

y = (-8/3)x + 67/3

Answer 2

Answer:y =
`(-8x)/(3) + (67)/(3)`

Explanation:

to do this, write t in terms of x, then substitute t in y

Write t in terms of x

x = -3t + 5

x - 5 = -3t

t = -x/3 + 5/3

Substitute t in y

t = -x/3 + 5/3

y = 8t + 9

y = 8(-x/3 + 5/3) + 9

y = -8x/3 + 40/3 + 9

y = -8x/3 + 40/3 + 27/3

y = -8x/3 + 67/3

y =
`(-8x)/(3) +(67)/(3)`