Question

A 63.5 g sample of an unidentified metal absorbs 355 ) of heat when its temperature changes

by 4.56 °C. Calculate the specific heat capacity of the metal.

Answer 1

0.208 is the specific heat capacity of the metal.

Step-by-step explanation:

Given:

mass (m) = 63.5 grams 0R 0.0635 kg

Heat absorbed (q) = 355 Joules

Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K

cp (specific heat capacity) = ?

the formula used for heat absorbed and to calculate specific heat capacity of a substance will be calculated by using the equation:

q = mc Δ T

c =
`(q)/(mΔ T)`

c =
`(355)/(63.5X 268.59)`

= 0.208 J/gm K

specific heat capacity of 0.208 J/gm K

The specific heat capacity is defined as the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.