Question

Write an equation in slope-intercept form of the line with the parametric equations x = -4t + 3 and y = 5t - 3.

A. y = 5/3x + 4/3
B. y = -5/3x + 4/3
C. y = 5/4x + 3/4
D. y = -5/4x + 3/4

Answer 1

D

Explanation:

x = -4t + 3

4t = 3 - x

t = (3 - x)/4

y = 5t - 3

y = 5(3 - x)/4 - 3

y = 15/4 - 5x/4 - 3

y = -5x/4 + 3/4

y = (-5/4)x + 3/4

Answer 2

Answer: D

Explanation:

Since both equations have the variable t, rewrite t in terms of x

x = -4t + 3

4t = 3 - x

t =
`(3-x)/(4)`

Now you can plug t into y

y = 5t - 3

y =
`5*(3-x)/(4) -3`

y =
`5*((3)/(4) - (x)/(4) ) -3`

y =
`(15)/(4) -(5x)/(4) -3`

y =
`(15)/(4) -(5x)/(4) -(12)/(4)`

y =
`(-5x)/(4) +(3)/(4)`