Final answer:
Pierre's velocity in the reference frame of the car is 47.37 m/s, and in the reference frame of the road, it is also 47.37 m/s. Pierre's trajectory in the reference frame of the road is curved, indicating circular motion.
Step-by-step explanation:
1a) To calculate Pierre's velocity in the reference frame of the car, we can use the formula:
Vc = d/t
Where Vc is the velocity in the reference frame of the car, d is the distance traveled, and t is the time taken. Given that Pierre travels 450 m in 9500 ms, we can plug these values into the formula:
Vc = 450 m / 9.5 s = 47.37 m/s
1b) To calculate Pierre's velocity in the reference frame of the road, we need to take into account the curvature of the turn. Since the velocity is constant in both cases, the magnitude of Pierre's velocity in the reference frame of the road will be the same: 47.37 m/s.
2. In the reference frame of the road, Pierre's trajectory will be curved, following the arc of the circle.
3. Since Pierre's trajectory is curved in the reference frame of the road, his motion can be classified as circular motion.