Question

Find the value of x. Round to the nearest tenth.

thank you in advance for the help! ​

Answer 1

x ≈ 3.1

Explanation:

Using Pythagoras' identity in the right triangle with hypotenuse 2.1 and

legs 1.4 and
`(1)/(2)` x, thus

(
`(1)/(2)` x )² + 1.4² = 2.1², that is

`(1)/(4)` x² + 1.96 = 4.41 ( subtract 1.96 from both sides )

`(1)/(4)` x² = 2.45 ( multiply both sides by 4 )

x² = 9.8 ( take the square root of both sides )

x ≈ 3.1 ( to the nearest tenth )

Answer 2

`{1.4}^(2) + {x}^(2) = {2.1}^(2) \\ 1.96 + {x}^(2) = 4.41 \\ {x}^(2) = 4.41 - 1.96 \\ {x}^(2) = 2.45 \\ x = √(2.45) \\ x = 3.12ft`

Explanation:

YOU HAVE TO USE THE PYTHAGORAS THEORAM