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A sugar has the formula C6H12O6. One mile of this sugar is burned completely in air. What is the minimum number of moles of CO2 that could be produced? A. 3 B. 9 C. 12 D. 6

2 Answers

5 votes

Answer: D. 6

Explanation: The balanced equation for the reaction is

C6H12O6 + 6O2 ---> 6CO2 + 6H2O.

One molecule of glucose burns completely in oxygen to produce six molecules of carbon and six moles of water.

Therefore the minimum number of moles of carbon dioxide produced by complete burning of C6H12O6 in air is 6.

User Bairog
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1 vote

Answer:

Option D. 6

Step-by-step explanation:

First, we'll begin by writing a balanced equation for the Combustion of the sugar in air. This is illustrated below:

C6H12O6 + 6O2 —> 6CO2 + 6H2O

From the balanced equation,

We can see that when 1 mole of the sugar (C6H12O6) is burned, 6 moles of CO2 are formed.

Therefore, option D is the correct answer.

User RecklessSergio
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3.7k points