Question

2

A tether ball tied to a pole by a rope swings in a circular path with a centripetal
acceleration of 2.7 m/s2. If the ball has a tangential speed of 2.0 m/s, what is the
diameter of the circular path in which it travels?
A 0.74 m
B 1.5 m
C 3.0 m
D 3.6 m

Answer 1

Diameter of the circle is 3.0 m

Step-by-step explanation:

As we know that the centripetal acceleration of the object moving in circular path is given as

`a_c = (v^2)/(R)`

so we have

`a_c = 2.7 m/s^2`

`v = 2 m/s`

now we have

`2.7 = (2^2)/(R)`

`R = 1.5 m`

So diameter of the circle is

d = 2R = 3.0 m