Question

Please help:
In Δ ABC, sin A= 82, sin B= 58, and b =27, find the length of A.

Answer 1

31.5

Explanation:

a/sinA = b/sinB

a/sin(82) = 27/sin(58)

a = sin(82) × 27/sin(58)

a = 31.52797345

Answer 2

A=32.17unit

Explanation:

As we know from the sine law that:

A/sin(alpha)=B/sin(beta)=C/sin(gama)

Where,

Therefore,

A/sin(Alpha)=B/sin(Beta)

A/82=27/58

A/82=0.465

A=0.465*82

A=32.17unit