Question

What is the equation of a line that contains points (1,7) and (5,3)

Answer 1

y=x+6

Explanation:

First find the slope.
`(y2-y1)/(x2-x1)`

`(3-7)/(5-1)` =
`(-4)/(4)`=-1

Then plug your slope and one of the points into point slope form.

y-y1=m(x-x1)

y-7=1(x-1)

y-7=x-1

y=x+6

Answer 2

Given points are x(1 , 7) and (5 , 3)

Explanation:

The equation of line is given by

y - y1 = ( y2 - y1 / x2 - x1) (x - x 1 )

y - 7 = (3 -7/5-1) ( x -1)

y -7 = -4/4 ( x -1 )

y - 7 = -1 (x -1)

y -7 = - x + 1

x + y - 7 -1 =0

x + y - 8 = 0

Which is the required equation.

Hope it will help you.