Question

Please, any help would be more than great!
3(a-4) ≥ 4 (a+5)

Answer 1

Inequality form is:
a (less or equal sign) -32
Interval form:
(-infinity , -32)

Answer 2

Hello there!

In order to solve this inequality, we should first use the distributive property:-

3(a-4)≥4(a+5)

3a-12≥4a+20

Now, add 12 to both sides:-

3a≥4a+32

Subtract 4a from both sides:-

3a-4a≥32

-a≥32

Divide both sides by -1:-

a≤-32

The inequality sign changed because we divided both sides by a negative number.

`\mathcal{NOTE:-}`

I hope everything is clear; however, if you need any explanation or clarification, don't hesitate to let me know, and I will comment or edit my answer. Good luck and have a great rest of your day! :)