Answer:
Step-by-step explanation:
Given that,
Mass place on spring is
M=0.25kg
Force constant of spring is
K=5000N/m
Compression of spring is
e=0.1m
The mass starts from rest, then it's initial velocity u=0m/s
Maximum height?
Energy in spring is converted to change in Potential energy and change in kinetic energy
Energy in spring is given as
U=½ke²
U=½×5000×0.1²
U=25J
Gravitational potential energy is given as
P.E = mgh
Where
m is mass
g is gravitational constant 9.81m/s²
h is height reached by object
Change in potential energy is given as
Not the initial height h of the object is zero h=0, so we want to find the final height (H)
∆P.E= mgH - mgh
∆P.E= 0.25×9.81×H -0.25×9.81×0
∆P.E= 2.4525H -0
∆P.E= 2.4525H
Change in kinetic energy is 0J, the object starts from rest then, it initial velocity is 0m/s and when it get to maximum height, the velocity at maximum height is 0m/s,
Change in kinetic energy is given as
∆K.E=½mVf² - ½mVi²
∆K.E= 0J
Therefore,
U= ∆P.E +∆K.E
25=2.4525H +0
2.4525H=25
H=25/2.4525
H=10.194m
Maximum height reached by the ball is 10.194m