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Sam has a jar contain 80 coins, all of which are either quarters or nickels. The total value of the coins is $14.60. How many of each type of coin does she have?

User Nastasha
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1 Answer

6 votes

Answer:

She have 53 type of quarters and 27 type of nickels.

Explanation:

Given:

Sam has a jar contain 80 coins, all of which are either quarters or nickels.

The total value of quarters and nickels is $14.60.

Now, to get each type of coin she have.

Let the number of quarters be
x.

And let the number of nickels be
y.

So, total number of coins:


x+y=80


y=80-x\ \ \ ....(1)

Now, the total value of coins:


0.25(x)+0.05(y)=14.60

Substituting the value of
y from equation (1):


0.25(x)+0.05(80-x)=14.60


0.25x+4-0.05x=14.60


0.20x+4=14.60

Subtracting both sides by 4 we get:


0.20x=10.60

Dividing both sides by 0.20 we get:


x=53.

The number of quarters = 53.

Now, to get the number of nickels by substituting the value of
x in equation (1):


y=80-x\\\\y=80-53\\\\y=27.

The number of nickels = 27.

Therefore, she have 53 type of quarters and 27 type of nickels.

User Pihentagy
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