Question

What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFraction EndRoot? Assume x ≠ 0.

StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction
StartFraction 6 Over 5 x squared EndFraction
Six-fifths x Superscript 10
Six-fifths x squared
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Answer 1

the answer is a

Explanation:

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Answer 2

StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Explanation:

Apparently you want to simplify ...

`\sqrt{(72x^(16))/(50x^(36))}`

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

(a^b)^c = a^(bc)

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So the expression simplifies as ...

`\sqrt{(72x^(16))/(50x^(36))}=\sqrt{(36)/(25x^(36-16))}=\sqrt{(36)/(25x^(20))}\\\\\sqrt{\left((6)/(5x^(10))\right)^2}=\boxed{(6)/(5x^(10))}`