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Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at 7.83 m/s, and Ethan, mass 31.0 kg, is gliding to the left at 10.1 m/s along the same line. When they meet, they grab each other and hang on.

That was so much fun that the boys repeat the collision with the same original velocities, this time moving along parallel lines 1.02 m apart. At closest aproach, they lock arms and start rotating about their common center of mass. Model the boys as particles and their arms as a cord that does not stretch.
Find the belocity of their center. magnitude _________m/s
direction __________

User Dan Jenson
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1 Answer

4 votes

Answer:

Step-by-step explanation:

They will rotate with some angular velocity about their common center of mass as well as their center of mass will have some velocity because , their momentum are not equal . .

momentum of Jacob = 45 x 7.83

= 352.35 kg m/s towards right

momentum of Ethan = 31 x 10.1

= 313.1 kg m/s towards left

net momentum towards right

= 352.35 - 313.1

= 39.25 unit

if common velocity be v

(45+ 31 ) v = 39.25

v = .5164 m / s

towards right .

User Vladislav Stepanov
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