Question

What is the work done on a 30 kg object if a force of 15 N is applied for 5 seconds?

Answer 1

Work done is 93.75J

Step-by-step explanation:

Given mass, m = 30kg; Time = 5 seconds; force = 15N; u= 0

Acceleration, a = F/m ⇒ 15/30

⇒ 0.5ms

Displacement , s= ut+1/2at²

⇒ 0 +1/2 (0.5*5*5)

⇒ 0 + 1/2(0.5*25)

⇒ 0 + 1/2(12.5)

⇒ 0 + 6.25

⇒ 6.25m

work done = Fs=15*6.25= 93.75 J