Question

Force A has a magnitude F and acts for the time Δt, force B has a magnitude 2F and acts for the time Δt/3, force C has a magnitude 5F and acts for the time Δt/10, and force D has a magnitude 10F and acts for the time Δt/100. Rank these forces in order of decreasing impulse.

Answer 1

`A>B>C>D`

Step-by-step explanation:

calculate impulse in each case:

As impulse is the product of force and time.

• Force A:

`I_A=F.\Delta t`

• Force B:

`I_B=2F.(\Delta t)/(3)=(2)/(3) * F.\Delta t`

• Force C:

`I_C=5F* (\Delta t)/(10) =(1)/(2) * F.\Delta t`

• Force D:

`I_D=10F* (\Delta t)/(100) =(1)/(10) F.\Delta t`

Now the force can be ranked as:

`A>B>C>D`