Question

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10 seconds, what is the value of impulse

A.
0.26 newton seconds
B.
0.58 newton seconds
C.
1.82 newton seconds
D.
2.20 newton seconds

Answer 1

Maybe the question is :

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is
`\sf{5.0 * 10^(-4)}` seconds, what is the value of impulse ?

So, the value of impulse is (A). 0.26 newton seconds.

Introduction

Hi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :

`\boxed{sf{\bold{I = F * \Delta t}}}`

With the following condition:

• I = impulse that occurs (N.s)
• F = force that given (N)
• 
  `\sf{\Delta t}` = interval of the time (s)

Problem Solving

We know that :

• F = force that given = 520 N
• 
  `\sf{\Delta t}` = interval of the time =
  `\sf{5.0 * 10^(-4) \: s}`

What was asked :

• I = impulse that occurs = ... N.s

Step by step :

`\sf{I = F * \Delta t}`

`\sf{I = 520 * (5.0 * 10^(-4)}`

`\sf{I = 2,600 * 10^(-4)}`

`\sf{I = 2.60 * 10^3 * 10^(-4)}`

`\sf{I = 2.60 * 10^(3 + (-4))}`

`\sf{I = 2.60 * 10^(-1) = \boxed{0.26 \: N.s}}`

Conclusion :

So, the value of impulse is (A). 0.26 newton seconds