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What is the energy of cell phone radiation with 1m wavelength

User DennisvB
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1 Answer

3 votes

Answer:


1.99\cdot 10^(-25) J

Step-by-step explanation:

Electromagnetic waves are oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light:


c=3.0\cdot 10^8 m/s

The energy of an electromagnetic wave is given by the equation:


E=(hc)/(\lambda)

where:


h=6.63\cdot 10^(-34)Js is the Planck constant


c=3.0\cdot 10^8 m/s is the speed of light


\lambda is the wavelength of the wave

In this problem, we have a wave with wavelength of


\lambda=1 m

So, its energy is:


E=((6.63\cdot 10^(-34))(3.0\cdot 10^8))/(1)=1.99\cdot 10^(-25) J

User Afaulconbridge
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